-16x^2+28x+30=42

Solution for -16x^2+28x+30=42 equation:

-16x^2+28x+30=42

We move all terms to the left:

-16x^2+28x+30-(42)=0

We add all the numbers together, and all the variables

-16x^2+28x-12=0

a = -16; b = 28; c = -12;
Δ = b2-4ac
Δ = 282-4·(-16)·(-12)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-4}{2*-16}=\frac{-32}{-32}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+4}{2*-16}=\frac{-24}{-32}
=3/4
$